What is the highest degree for the expression  (3x2+4)(x5−3)−12x9−24x3x+2 ?(1 point)Responses99778810

1 answer

To find the highest degree of the expression \( (3x^2 + 4)(x^5 - 3) - 12x^9 - 24x^3 + 2 \), we need to calculate the degree of each term in the expression.

  1. First term: \( (3x^2 + 4)(x^5 - 3) \)

    • The degree of \( 3x^2 \) is 2.
    • The degree of \( x^5 \) is 5.
    • The degree of the product \( (3x^2)(x^5) = 3x^{2+5} = 3x^7 \), which has a degree of 7.
    • The constant term \( 4 \) multiplied by \( x^5 \) contributes \( 4x^5 \) which has a degree of 5.
    • The total highest degree from \( (3x^2 + 4)(x^5 - 3) \) is therefore \( \max(7, 5) = 7 \).
  2. Second term: \( -12x^9 \)

    • This term has a degree of 9.
  3. Third term: \( -24x^3 \)

    • This term has a degree of 3.
  4. Fourth term: \( +2 \)

    • This is a constant, so its degree is 0.

Now, we compare all the degrees we calculated:

  • From \( (3x^2 + 4)(x^5 - 3) \), the maximum degree is 7.
  • From \( -12x^9 \), the degree is 9.
  • From \( -24x^3 \), the degree is 3.
  • From \( +2 \), the degree is 0.

The highest degree among these is 9.

Thus, the highest degree of the entire expression is \( \boxed{9} \).