First you need to solve for k.
280 = 250 e^(10k)
1.12 = e^(10k)
ln 1.12 = 0.13929 = 10 k
k = 1.1333*10^-2
The doubling time T is given by
N/No = e^kT = 2
kT = ln 2 = 0.693
T = 0.693/k = 61.2 hours
1) The number of bacteria N in a culture is given by N=250e^kt where t is the time in hours. If N = 280 when t=10 estimate the time required for the population to double in size.
280 = 250e^10k
divide by 250
1.12 = e^10k
ln 1.12 / 10 = .011 K = 0.11
Now I do not know what to do!
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