Question

In 2012
, the world's largest pumpkin weighed 913
kilograms. An average-sized pumpkin weighs 5000
grams.

The
world-record pumpkin weighs blank kilograms more than an average-sized pumpkin. (Write your answer as a numeral.)

Answer 1

First, we need to convert the weight of the average-sized pumpkin from grams to kilograms. Since 1 kilogram equals 1000 grams, we can perform the following calculation:

\[
\text{Average-sized pumpkin weight in kg} = \frac{5000 \text{ grams}}{1000 \text{ grams/kg}} = 5 \text{ kg}
\]

Now, we can find out how much more the world-record pumpkin weighs compared to the average-sized pumpkin by subtracting the weight of the average pumpkin from that of the world-record pumpkin:

\[
\text{Weight difference} = \text{World-record pumpkin weight} - \text{Average-sized pumpkin weight}
\]

Substituting the weights:

\[
\text{Weight difference} = 913 \text{ kg} - 5 \text{ kg} = 908 \text{ kg}
\]

Thus, the world-record pumpkin weighs **908** kilograms more than an average-sized pumpkin.