Solve for x: 20x - 5(6x + 15) = -45.

Question

A. x = -3
B. x = -2
C. x = 3
D. x = 2

Answer 1

To solve the equation \( 20x - 5(6x + 15) = -45 \), we start by distributing the \(-5\) into the parentheses:

\[ 20x - 5(6x) - 5(15) = -45 \]

This simplifies to:

\[ 20x - 30x - 75 = -45 \]

Next, we combine like terms:

\[ (20x - 30x) - 75 = -45 \] \[ -10x - 75 = -45 \]

Now, we can isolate the term with \(x\) by adding \(75\) to both sides:

\[ -10x = -45 + 75 \] \[ -10x = 30 \]

Next, we divide both sides by \(-10\):

\[ x = \frac{30}{-10} \] \[ x = -3 \]

Thus, the solution is:

\[ \boxed{-3} \]

The correct answer is A. x = -3.

Answer 2

are you sure this is correct

Answer 3

Let’s double-check the solution step-by-step to ensure that it’s accurate.

We start with the original equation:

\[ 20x - 5(6x + 15) = -45 \]

Now, we will distribute the \(-5\) into the parentheses:

\[ 20x - (5 \cdot 6x) - (5 \cdot 15) = -45 \]

This becomes:

\[ 20x - 30x - 75 = -45 \]

Next, we combine like terms (\(20x - 30x\)):

\[ -10x - 75 = -45 \]

Now, we isolate the term with \(x\) by adding \(75\) to both sides:

\[ -10x = -45 + 75 \] \[ -10x = 30 \]

Finally, we divide both sides by \(-10\):

\[ x = \frac{30}{-10} \] \[ x = -3 \]

So, the solution remains:

\[ \boxed{-3} \]

The original solution is indeed correct. The answer is A. \( x = -3 \).