Question

Solve for x: 20x - 5(6x + 15) = -45.
A. x = -3
B. x = -2
C. x = 3
D. x = 2

Answer 1

are you sure this is correct

Answer 2

To solve the equation \( 20x - 5(6x + 15) = -45 \), we start by distributing the \(-5\) into the parentheses:

\[
20x - 5(6x) - 5(15) = -45
\]

This simplifies to:

\[
20x - 30x - 75 = -45
\]

Next, we combine like terms:

\[
(20x - 30x) - 75 = -45
\]
\[
-10x - 75 = -45
\]

Now, we can isolate the term with \(x\) by adding \(75\) to both sides:

\[
-10x = -45 + 75
\]
\[
-10x = 30
\]

Next, we divide both sides by \(-10\):

\[
x = \frac{30}{-10}
\]
\[
x = -3
\]

Thus, the solution is:

\[
\boxed{-3}
\]

The correct answer is A. x = -3.

Answer 3

Let’s double-check the solution step-by-step to ensure that it’s accurate.

We start with the original equation:

\[
20x - 5(6x + 15) = -45
\]

Now, we will distribute the \(-5\) into the parentheses:

\[
20x - (5 \cdot 6x) - (5 \cdot 15) = -45
\]

This becomes:

\[
20x - 30x - 75 = -45
\]

Next, we combine like terms (\(20x - 30x\)):

\[
-10x - 75 = -45
\]

Now, we isolate the term with \(x\) by adding \(75\) to both sides:

\[
-10x = -45 + 75
\]
\[
-10x = 30
\]

Finally, we divide both sides by \(-10\):

\[
x = \frac{30}{-10}
\]
\[
x = -3
\]

So, the solution remains:

\[
\boxed{-3}
\]

The original solution is indeed correct. The answer is A. \( x = -3 \).