Question
The chandelier in my house has about 339 J of potential energy. if it is 3 meters off the ground, what is the mass of the chandelier?
Answers
GPT-4o mini
To find the mass of the chandelier, we can use the formula for gravitational potential energy (PE):
\[
PE = mgh
\]
where:
- \( PE \) is the potential energy (in joules),
- \( m \) is the mass (in kilograms),
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)),
- \( h \) is the height (in meters).
We know that:
- \( PE = 339 \, \text{J} \)
- \( h = 3 \, \text{m} \)
- \( g = 9.81 \, \text{m/s}^2 \)
We can rearrange the equation to solve for \( m \):
\[
m = \frac{PE}{gh}
\]
Now we can substitute in the known values:
\[
m = \frac{339 \, \text{J}}{(9.81 \, \text{m/s}^2)(3 \, \text{m})}
\]
Calculating the denominator:
\[
9.81 \, \text{m/s}^2 \times 3 \, \text{m} = 29.43 \, \text{m}^2/\text{s}^2
\]
Now, substitute this result back into the equation for \( m \):
\[
m = \frac{339 \, \text{J}}{29.43 \, \text{m}^2/\text{s}^2} \approx 11.52 \, \text{kg}
\]
So, the mass of the chandelier is approximately **11.52 kg**.
\[
PE = mgh
\]
where:
- \( PE \) is the potential energy (in joules),
- \( m \) is the mass (in kilograms),
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)),
- \( h \) is the height (in meters).
We know that:
- \( PE = 339 \, \text{J} \)
- \( h = 3 \, \text{m} \)
- \( g = 9.81 \, \text{m/s}^2 \)
We can rearrange the equation to solve for \( m \):
\[
m = \frac{PE}{gh}
\]
Now we can substitute in the known values:
\[
m = \frac{339 \, \text{J}}{(9.81 \, \text{m/s}^2)(3 \, \text{m})}
\]
Calculating the denominator:
\[
9.81 \, \text{m/s}^2 \times 3 \, \text{m} = 29.43 \, \text{m}^2/\text{s}^2
\]
Now, substitute this result back into the equation for \( m \):
\[
m = \frac{339 \, \text{J}}{29.43 \, \text{m}^2/\text{s}^2} \approx 11.52 \, \text{kg}
\]
So, the mass of the chandelier is approximately **11.52 kg**.
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