olve for x: −4(3x+10)−2=54.(1 point) Responses

3 answers

To solve the equation \(-4(3x + 10) - 2 = 54\), let's follow the steps:

  1. Distribute \(-4\) to the terms inside the parentheses: \[ -4 \cdot 3x - 4 \cdot 10 - 2 = 54 \] This simplifies to: \[ -12x - 40 - 2 = 54 \]

  2. Combine the constants: \[ -12x - 42 = 54 \]

  3. Add \(42\) to both sides to isolate the term with \(x\): \[ -12x = 54 + 42 \] This simplifies to: \[ -12x = 96 \]

  4. Divide both sides by \(-12\): \[ x = \frac{96}{-12} \] This simplifies to: \[ x = -8 \]

So the solution is: \[ \boxed{-8} \]

Solve for x : 20x−5(6x+15)=−45 .(1 point)

To solve the equation \(20x - 5(6x + 15) = -45\), follow these steps:

  1. Distribute the \(-5\) to the terms inside the parentheses: \[ 20x - 5 \cdot 6x - 5 \cdot 15 = -45 \] This simplifies to: \[ 20x - 30x - 75 = -45 \]

  2. Combine like terms on the left side: \[ (20x - 30x) - 75 = -45 \] This simplifies to: \[ -10x - 75 = -45 \]

  3. Add \(75\) to both sides to isolate the term with \(x\): \[ -10x = -45 + 75 \] This simplifies to: \[ -10x = 30 \]

  4. Divide both sides by \(-10\): \[ x = \frac{30}{-10} \] This simplifies to: \[ x = -3 \]

So the solution is: \[ \boxed{-3} \]