To simplify the expression \(\frac{9/35}{9/15}\) using the Quotient Property, we can rewrite the division of fractions as follows:
\[ \frac{9/35}{9/15} = \frac{9}{35} \div \frac{9}{15} \]
When dividing fractions, we multiply by the reciprocal of the divisor:
\[ \frac{9}{35} \div \frac{9}{15} = \frac{9}{35} \times \frac{15}{9} \]
Now we can simplify:
- The \(9\) in the numerator of \(\frac{9}{35}\) cancels with the \(9\) in the denominator of \(\frac{15}{9}\).
This gives us:
\[ \frac{15}{35} \]
Next, we can simplify \(\frac{15}{35}\) by finding the greatest common divisor (GCD) of \(15\) and \(35\), which is \(5\):
\[ \frac{15 \div 5}{35 \div 5} = \frac{3}{7} \]
Thus, the simplified expression for \(\frac{9/35}{9/15}\) is:
\[ \frac{3}{7} \]
If we were to interpret your question about "the simplified exponent", it may depend on a specific context about how you want to incorporate exponents in any terms present. However, the final result of \(\frac{9/35}{9/15}\) simplifies to \(\frac{3}{7}\).
If there is a specific exponent-related context you want to explore, please clarify so that I can provide the appropriate details!