Question

Find the perimeter of a square with a side length of 2√12 . Your answer must be in simplest radical form.(1 point)

answer choices (select the one that is 100% correct)

16√3
8√48
32√3
8√12

Answer 1

To find the perimeter of a square, we use the formula:

\[
\text{Perimeter} = 4 \times \text{side length}
\]

In this case, the side length is \(2\sqrt{12}\).

First, we calculate the perimeter:

\[
\text{Perimeter} = 4 \times 2\sqrt{12} = 8\sqrt{12}
\]

Next, we simplify \(\sqrt{12}\):

\[
\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}
\]

Now substituting back, we get:

\[
8\sqrt{12} = 8 \times 2\sqrt{3} = 16\sqrt{3}
\]

Thus, the perimeter of the square in simplest radical form is:

\[
\boxed{16\sqrt{3}}
\]

The correct answer choice from your options is **16√3**.