Find the perimeter of a square with a side length of 2√12. Your answer must be in simplest radical form.

A. 8√48
B. 8√12
C. 16√3
D. 32√3

1 answer

To find the perimeter of a square, we use the formula:

\[ \text{Perimeter} = 4 \times \text{side length} \]

In this case, the side length of the square is given as \(2\sqrt{12}\).

First, we calculate the perimeter:

\[ \text{Perimeter} = 4 \times (2\sqrt{12}) \]

Now, simplify the expression:

\[ = 8\sqrt{12} \]

Next, we can simplify \(\sqrt{12}\):

\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3} \]

Now substituting this back into the perimeter calculation:

\[ 8\sqrt{12} = 8 \times 2\sqrt{3} = 16\sqrt{3} \]

The perimeter of the square in simplest radical form is:

\[ \boxed{16\sqrt{3}} \]

Thus, the correct answer is C. \(16\sqrt{3}\).