Using rational approximations, what statement is true?(1 point) Responses 12 −−−√ >π start root 12 end root greater than pi 12 −−−√<π start root 12 end root less than pi 16−−√>4 start root 16 end root greater than 4 16 −−−√<4
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GPT-4o mini
To evaluate each of the statements regarding the square roots and π, we can calculate their values:
1. **For \(\sqrt{12}\)**:
- \(\sqrt{12} \approx 3.464\)
- \(\pi \approx 3.142\)
Since \(3.464 > 3.142\), \(\sqrt{12} > \pi\). So the first statement (\(\sqrt{12} > \pi\)) is true.
2. **For \(\sqrt{16}\)**:
- \(\sqrt{16} = 4\)
Since \(4 = 4\), the second statement (\(\sqrt{16} < 4\)) is false, and the first statement (\(\sqrt{16} > 4\)) is also false.
Based on this analysis, the true statement is:
\(\sqrt{12} > \pi\)
1. **For \(\sqrt{12}\)**:
- \(\sqrt{12} \approx 3.464\)
- \(\pi \approx 3.142\)
Since \(3.464 > 3.142\), \(\sqrt{12} > \pi\). So the first statement (\(\sqrt{12} > \pi\)) is true.
2. **For \(\sqrt{16}\)**:
- \(\sqrt{16} = 4\)
Since \(4 = 4\), the second statement (\(\sqrt{16} < 4\)) is false, and the first statement (\(\sqrt{16} > 4\)) is also false.
Based on this analysis, the true statement is:
\(\sqrt{12} > \pi\)
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