Use the table to answer the question.

To find the product of \( (4x^3 + 2x^2)(6x - 9) \), we'll use the distributive property (also known as the FOIL method for binomials).

1. Distribute \( 4x^3 \) to both terms in the second polynomial \( (6x - 9) \):
\[
4x^3 \cdot 6x = 24x^4
\]
\[
4x^3 \cdot (-9) = -36x^3
\]

2. Distribute \( 2x^2 \) to both terms in the second polynomial \( (6x - 9) \):
\[
2x^2 \cdot 6x = 12x^3
\]
\[
2x^2 \cdot (-9) = -18x^2
\]

3. Now, combine all the products obtained:
\[
(4x^3 + 2x^2)(6x - 9) = 24x^4 - 36x^3 + 12x^3 - 18x^2
\]

4. Combine like terms:
\[
-36x^3 + 12x^3 = -24x^3
\]

5. So, the complete expression is:
\[
24x^4 - 24x^3 - 18x^2
\]

Thus, the product is:
\[
(4x^3 + 2x^2)(6x - 9) = 24x^4 - 24x^3 - 18x^2
\]