Asked by KiKi

How many mL of 0.0875 M H2SO4 would you need to exactly neutralize 50.00 mL of 0.135 M NaOH?
Answered by DrBob222
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

moles NaOH = M x L
moles H2SO4 needed (from the equation) = 1/2 moles NaOH.

moles H2SO4 = M x L. YOu know moles and M, calculate L, then convert to mL.
Answered by Man
Man Man
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