Solve for x

Question

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8x−14=10

Answer 1

To solve the equation \( 8x - 14 = 10 \), follow these steps:

1. Add 14 to both sides of the equation to isolate the term with \( x \): \[ 8x - 14 + 14 = 10 + 14 \] \[ 8x = 24 \]

2. Divide both sides by 8 to solve for \( x \): \[ x = \frac{24}{8} \] \[ x = 3 \]

Thus, the solution is \( x = 3 \).

Answer 2

Solve for x
.
−5x−11=19

Answer 3

To solve the equation \(-5x - 11 = 19\), follow these steps:

1. Add 11 to both sides to isolate the term with \(x\): \[ -5x - 11 + 11 = 19 + 11 \] \[ -5x = 30 \]

2. Divide both sides by -5 to solve for \(x\): \[ x = \frac{30}{-5} \] \[ x = -6 \]

Thus, the solution is \(x = -6\).

Answer 4

Solve for x
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x over 4 − 2 = −10

Answer 5

To solve the equation

\[ \frac{x}{4} - 2 = -10, \]

follow these steps:

1. Add 2 to both sides to isolate the fraction: \[ \frac{x}{4} - 2 + 2 = -10 + 2 \] \[ \frac{x}{4} = -8. \]

2. Multiply both sides by 4 to eliminate the fraction: \[ 4 \cdot \frac{x}{4} = -8 \cdot 4 \] \[ x = -32. \]

Thus, the solution is \(x = -32\).

Answer 6

Solve for x
.
−4 over 3x + 2 = 10

Answer 7

To solve the equation

\[ -\frac{4}{3}x + 2 = 10, \]

follow these steps:

1. Subtract 2 from both sides to isolate the term with \(x\): \[ -\frac{4}{3}x + 2 - 2 = 10 - 2 \] \[ -\frac{4}{3}x = 8. \]

2. Multiply both sides by \(-\frac{3}{4}\) to solve for \(x\) (this is the reciprocal of \(-\frac{4}{3}\)): \[ x = 8 \cdot \left(-\frac{3}{4}\right). \] \[ x = -6. \]

Thus, the solution is \(x = -6\).

Answer 8

Solve for x
.
3 − 5 over 3x = 18

Answer 9

To solve the equation

\[ 3 - \frac{5}{3}x = 18, \]

follow these steps:

1. Subtract 3 from both sides to isolate the term with \(x\): \[ 3 - 3 - \frac{5}{3}x = 18 - 3 \] \[ -\frac{5}{3}x = 15. \]

2. Multiply both sides by \(-\frac{3}{5}\) to solve for \(x\): \[ x = 15 \cdot \left(-\frac{3}{5}\right). \] \[ x = -9. \]

Thus, the solution is \(x = -9\).