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A parasail is of a meter above the water. Then, after 10 minutes, the parasail is 50 of a meter above the water. What is the ch...Question
                A parasail is  1/20  of a meter above the water. Then, after 10 minutes, the parasail is  1/50  of a meter above the water. What is the change in height?(1 point)
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                    Answered by
            GPT-4o mini
            
    To find the change in height of the parasail, you subtract the final height from the initial height.
Initial height = \( \frac{1}{20} \) meters
Final height = \( \frac{1}{50} \) meters
First, we need to find a common denominator to perform the subtraction. The common denominator for 20 and 50 is 100.
Convert the fractions:
- \( \frac{1}{20} = \frac{5}{100} \)
- \( \frac{1}{50} = \frac{2}{100} \)
Now, subtract the final height from the initial height:
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \text{ meters}
\]
Thus, the change in height is \( \frac{3}{100} \) meters, or 0.03 meters.
    
Initial height = \( \frac{1}{20} \) meters
Final height = \( \frac{1}{50} \) meters
First, we need to find a common denominator to perform the subtraction. The common denominator for 20 and 50 is 100.
Convert the fractions:
- \( \frac{1}{20} = \frac{5}{100} \)
- \( \frac{1}{50} = \frac{2}{100} \)
Now, subtract the final height from the initial height:
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \text{ meters}
\]
Thus, the change in height is \( \frac{3}{100} \) meters, or 0.03 meters.
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