Question

What is wrong with the following code? Scanner input = new Scanner(System.in); String s = nextLine(); Group of answer choices Should be: String s = input.nextLine(); Nothing is wrong, that code won't generate any errors. Should be: String s = input.next; nextLine() method can't work with String variables Should be: String s = next();

Answer 1

The issue with the code you provided is in the way the `nextLine()` method is called. Specifically, the correct way to call `nextLine()` is on the `input` object, which is an instance of the `Scanner` class.

Here is the correct line of code:

```java
String s = input.nextLine();
```

This means the correct choice from the options you provided would be:

**Should be: String s = input.nextLine();**

The other options are incorrect for the following reasons:

- "Nothing is wrong, that code won't generate any errors." - This is incorrect because the code as written will result in a compilation error since `nextLine()` is not being called on the `Scanner` object.

- "Should be: String s = input.next;" - This is incorrect. The `next()` method reads the next token (word) rather than a full line, and it's not the correct method to call.

- "nextLine() method can't work with String variables" - This statement is misleading. The `nextLine()` method returns a `String`, and it can indeed be assigned to a `String` variable.

So, the correct answer is that the code should be modified to call `nextLine()` on the `input` object.