Given that the cube root of 27 is 3, what is 2743

To solve for \( 2743 \), we need to interpret the expression correctly. The expression typically should be clear, but it looks like there might be a small confusion.

If you meant to ask for \( 27^{4/3} \) (which could be thought of as \( 27^{2} \) taken to the power of \( \frac{2}{3} \)), we can compute that as follows:

1. Given that the cube root of 27 is 3, we can express 27 as \( 3^3 \).
2. Thus, \( 27^2 \) is:
\[
(3^3)^2 = 3^{3 \times 2} = 3^6 = 729
\]
3. For \( 27^{\frac{4}{3}} \):
\[
(3^3)^{\frac{4}{3}} = 3^{3 \times \frac{4}{3}} = 3^4 = 81
\]

So, \( 27^{4/3} = 81 \).

Therefore, the correct answer to the problem is:

**81**