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To solve for \( 2743 \), we need to interpret the expression correctly. The expression typically should be clear, but it looks like there might be a small confusion.
If you meant to ask for \( 27^{4/3} \) (which could be thought of as \( 27^{2} \) taken to the power of \( \frac{2}{3} \)), we can compute that as follows:
1. Given that the cube root of 27 is 3, we can express 27 as \( 3^3 \).
2. Thus, \( 27^2 \) is:
\[
(3^3)^2 = 3^{3 \times 2} = 3^6 = 729
\]
3. For \( 27^{\frac{4}{3}} \):
\[
(3^3)^{\frac{4}{3}} = 3^{3 \times \frac{4}{3}} = 3^4 = 81
\]
So, \( 27^{4/3} = 81 \).
Therefore, the correct answer to the problem is:
**81**