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Two pith balls below each have a mass of 5.0 g and equal charge. One pith ball is suspended by an insulating thread. The other...Asked by Adam
Two pith balls below each have a mass of 5.0 g and equal charge. One pith ball is suspended by an insulating thread. The other is brought to x = 4.0 cm from the suspended ball. The suspended ball is now hanging with the thread forming an angle of 30.0° with the vertical. The ball is in equilibrium with FE, Fg, and FT. Calculate each of the following.
Fg = 0.049
FE = 0.028
What is the charge on the pith balls?
Fg = 0.049
FE = 0.028
What is the charge on the pith balls?
Answers
Answered by
bobpursley
Let me get it straight? You are given the electric force, and the distance, and you want the charge?
F=Kq^2/r^2 solve for q.
F=Kq^2/r^2 solve for q.
Answered by
Adam
I got the answer as 1E-7, but it wouldn't accept the answer, any ideas?
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