Question
Simplify the polynomial expression (xy - 2)(x ^ 2 + 1) . Box x ^ 3 * y + Box x^ 2 + Box xy+ Box
Answers
Answered by
GPT-4o mini
To simplify the polynomial expression \((xy - 2)(x^2 + 1)\), we can use the distributive property (also known as the FOIL method for binomials):
1. Distributing \(xy\):
\[
xy \cdot x^2 = x^3y
\]
\[
xy \cdot 1 = xy
\]
2. Distributing \(-2\):
\[
-2 \cdot x^2 = -2x^2
\]
\[
-2 \cdot 1 = -2
\]
Now, we combine all these results:
\[
x^3y + xy - 2x^2 - 2
\]
Rearranging gives us:
\[
x^3y - 2x^2 + xy - 2
\]
Now we can put the terms with common factors together if needed, but as the original expression seems to be structured into boxes, we can group the result:
- \(Box = x^3y\)
- \(Box = -2x^2\)
- \(Box = xy\)
- \(Box = -2\)
Thus, the simplified expression is:
\[
\boxed{x^3y} + \boxed{-2x^2} + \boxed{xy} + \boxed{-2}
\]
1. Distributing \(xy\):
\[
xy \cdot x^2 = x^3y
\]
\[
xy \cdot 1 = xy
\]
2. Distributing \(-2\):
\[
-2 \cdot x^2 = -2x^2
\]
\[
-2 \cdot 1 = -2
\]
Now, we combine all these results:
\[
x^3y + xy - 2x^2 - 2
\]
Rearranging gives us:
\[
x^3y - 2x^2 + xy - 2
\]
Now we can put the terms with common factors together if needed, but as the original expression seems to be structured into boxes, we can group the result:
- \(Box = x^3y\)
- \(Box = -2x^2\)
- \(Box = xy\)
- \(Box = -2\)
Thus, the simplified expression is:
\[
\boxed{x^3y} + \boxed{-2x^2} + \boxed{xy} + \boxed{-2}
\]
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