(b) (i)

Hawa walked two fifth of her journey, John walked three eighth of his journey. If these two people have the same length of their journey, who walked the shortest distance?

1 answer

To determine who walked the shortest distance, we first need to express the distances Hawa and John walked in a comparable way based on the lengths of their journeys.

Let the total length of Hawa's journey be represented as H and the total length of John's journey as J.

According to the problem:

  • Hawa walked 25H
  • John walked 38J

Since they have the same length of their journeys, we can set H=J.

Step 1: Use H=J

Let’s denote the journey length as D (where D=H=J). Hence:

  • Hawa walked 25D
  • John walked 38D

Step 2: Compare the distances walked

Now we calculate the distances Hawa and John walked in terms of D:

  1. Hawa's Distance: Distance Hawa walked=25D

  2. John's Distance: Distance John walked=38D

Step 3: Find a common denominator to compare

To compare 25D and 38D, we can find a common denominator. The least common multiple of 5 and 8 is 40.

Converting each fraction:

  • For Hawa: 25D=2×85×8D=1640D

  • For John: 38D=3×58×5D=1540D

Step 4: Compare the two distances

Now we can compare:

  • Hawa's distance: 1640D
  • John's distance: 1540D

Since 1640D>1540D, we find that:

  • Hawa walked more distance than John.

Conclusion

Thus, John walked the shortest distance.