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select the choice that indicates a b is the perpendicular bisector of cd if they intersect at pQuestion
Select the choice that indicates AB←→ is the perpendicular bisector of CD←→ if they intersect at P .
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Answered by
Your teacher
You should provide what the answer choices are.
But it should be CD ⊥ AB and CP≅DP
But it should be CD ⊥ AB and CP≅DP
Answered by
GPT-4o mini
For \( AB \) to be the perpendicular bisector of \( CD \), the following must be true:
1. \( P \) is the midpoint of \( CD \).
2. \( AB \) intersects \( CD \) at \( P \).
3. \( AB \) is perpendicular to \( CD \) at \( P \).
Therefore, if you are given a choice indicating these three criteria, that would be the one that identifies \( AB \) as the perpendicular bisector of \( CD \) at the point \( P \). If you have specific choices listed, please provide them for further assistance.
1. \( P \) is the midpoint of \( CD \).
2. \( AB \) intersects \( CD \) at \( P \).
3. \( AB \) is perpendicular to \( CD \) at \( P \).
Therefore, if you are given a choice indicating these three criteria, that would be the one that identifies \( AB \) as the perpendicular bisector of \( CD \) at the point \( P \). If you have specific choices listed, please provide them for further assistance.
Answered by
GPT-4o mini
Given the information that \( AB \) is the perpendicular bisector of \( CD \) and they intersect at \( P \), the correct choice would be:
**\( CD \perp AB \) and \( CP \cong DP \)**
This means:
1. \( CD \perp AB \) indicates that \( AB \) is perpendicular to \( CD \).
2. \( CP \cong DP \) indicates that point \( P \) is the midpoint of segment \( CD \), meaning \( CP \) is congruent to \( DP \).
Both conditions together confirm that \( AB \) is indeed the perpendicular bisector of \( CD \).
**\( CD \perp AB \) and \( CP \cong DP \)**
This means:
1. \( CD \perp AB \) indicates that \( AB \) is perpendicular to \( CD \).
2. \( CP \cong DP \) indicates that point \( P \) is the midpoint of segment \( CD \), meaning \( CP \) is congruent to \( DP \).
Both conditions together confirm that \( AB \) is indeed the perpendicular bisector of \( CD \).
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