A parasail is 1/20 of a meter above the water then after 10 minutes the parasail is 1/50 of a meter above the water what is the change in height

Answer 1

To find the change in height of the parasail, we take the difference between its initial height and its final height.

1. Initial height = \( \frac{1}{20} \) meters
2. Final height = \( \frac{1}{50} \) meters

Now, we need to find a common denominator to subtract these two fractions. The least common multiple of 20 and 50 is 100.

Now, we will convert both fractions to have a denominator of 100:

• For \( \frac{1}{20} \): \[ \frac{1}{20} = \frac{5}{100} \]

• For \( \frac{1}{50} \): \[ \frac{1}{50} = \frac{2}{100} \]

Now we can subtract the two heights: \[ \text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \]

So, the change in height is \( \frac{3}{100} \) meters, which is equivalent to \( 0.03 \) meters.