what is 8- 7 1/4

3 answers

To solve \( 8 - 7 \frac{1}{4} \), first convert \( 7 \frac{1}{4} \) into an improper fraction.

  1. Convert \( 7 \frac{1}{4} \): \[ 7 \frac{1}{4} = 7 + \frac{1}{4} = \frac{7 \times 4}{4} + \frac{1}{4} = \frac{28}{4} + \frac{1}{4} = \frac{29}{4} \]

  2. Now subtract \( 8 \) from \( \frac{29}{4} \). First, convert \( 8 \) into a fraction with a denominator of \( 4 \): \[ 8 = \frac{8 \times 4}{4} = \frac{32}{4} \]

  3. Now perform the subtraction: \[ \frac{32}{4} - \frac{29}{4} = \frac{32 - 29}{4} = \frac{3}{4} \]

So, \( 8 - 7 \frac{1}{4} = \frac{3}{4} \).

-4 5/11 - 2 4/11

To solve \(-4 \frac{5}{11} - 2 \frac{4}{11}\), we first convert both mixed numbers into improper fractions.

  1. Convert \(-4 \frac{5}{11}\): \[ -4 \frac{5}{11} = -\left(4 \times 11 + 5\right) = -\left(44 + 5\right) = -\frac{49}{11} \]

  2. Convert \(-2 \frac{4}{11}\): \[ -2 \frac{4}{11} = -\left(2 \times 11 + 4\right) = -\left(22 + 4\right) = -\frac{26}{11} \]

Now, we can subtract the two improper fractions: \[ -\frac{49}{11} - \frac{26}{11} = -\left(\frac{49 + 26}{11}\right) = -\frac{75}{11} \]

Next, we can convert \(-\frac{75}{11}\) back into a mixed number:

  • Divide \(75\) by \(11\):
    • \(75 \div 11 = 6\) (whole number part) remainder \(9\).

So, \[ -\frac{75}{11} = -6 \frac{9}{11} \]

Thus, the final answer is: \[ -4 \frac{5}{11} - 2 \frac{4}{11} = -6 \frac{9}{11} \]