Question

0.25 g of acid is titrated with .108 M NaOH. if it takes 27.22 mL of NaOH to reach the endpoint, what is the equivalent weight of the acid?

Answer 1

mL x N x milliequivalnt weight = grams
The normality of NaOH is the same as the molarity.

Answer 2

Multiply me wt by 1000 to obtain equivalent weight.