Question

The punter on a football team tries to kick a football so that it stays in the air for a long "hang time." If the ball is kicked with an initial velocity of 25.0 m/s at an angle of 57.5° above the ground, what is the "hang time"?
The hang time is twice the time it takes for the vertical velocity component (which in initially 25.0 sin 57.5 m/s) to reach zero. That equals twice the time it takes to reach its highest elevation.

T = 2 Vo sin 57.5/g

g is the acceleration of gravity.

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