Use the image to answer the question.

The length, width, and height of a cube are all labeled a.

A cube has an edge length, a
, that is a rational number of centimeters. Identify which measurement will require the use of irrational numbers.

(1 point)
Responses

the diagonal of one of the cube’s faces
the diagonal of one of the cube’s faces

the surface area of the cube
the surface area of the cube

the volume of the cube
the volume of the cube

the area of one of the cube’s face

1 answer

To determine which measurement will require the use of irrational numbers, we can analyze each option given the edge length \( a \):

  1. The diagonal of one of the cube’s faces: The diagonal of a face of a cube can be calculated using the Pythagorean theorem. For a face with side length \( a \), the diagonal (d) is given by: \[ d = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2} \] Since \( a \) is a rational number, \( a\sqrt{2} \) is irrational because \( \sqrt{2} \) is irrational.

  2. The surface area of the cube: The surface area (SA) of a cube is calculated as: \[ SA = 6a^2 \] This is a rational number, as the square of a rational number ( \( a^2 \) ) is rational, and multiplying by 6 keeps it rational.

  3. The volume of the cube: The volume (V) of a cube is calculated as: \[ V = a^3 \] This is also a rational number because the cube of a rational number is rational.

  4. The area of one of the cube’s face: The area (A) of one face is: \[ A = a^2 \] Again, this is a rational number since the square of a rational number is rational.

Based on this analysis, the only measurement that requires the use of irrational numbers is:

The diagonal of one of the cube’s faces.

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