To determine the approximate value of the square root of 28, we can find the square roots of the perfect squares around it.
- The square root of 25 is 5 (since \(5^2 = 25\)).
- The square root of 36 is 6 (since \(6^2 = 36\)).
Since \(28\) is between \(25\) and \(36\), it follows that:
\[ 5 < \sqrt{28} < 6 \]
Next, let's determine if it is closer to 5 or 6.
Calculating more precisely:
- \(5.5^2 = 30.25\)
- \(5.3^2 = 28.09\)
- \(5.2^2 = 27.04\)
Since \(5.3^2\) is very close to \(28\), we conclude that \(\sqrt{28}\) is indeed between \(5.3\) and \(5.4\), but closer to \(5.3\).
Thus, the accurate statement is:
It is between 5 and 6, probably closer to 5.