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Graph the piecewise function f(x)={x+5 if x≤−22x+3 if x>−2 . Will the graph have any open endpoints? If yes, where?(1 point) Re...Question
Graph the piecewise function f(x)={x+5 if x≤−22x+3 if x>−2. Will the graph have any open endpoints? If yes, where?(1 point)
Responses
No, all endpoints are closed.
No, all endpoints are closed.
Yes, at (−2,3).
Yes, at left parenthesis negative 2 comma 3 right parenthesis .
Yes, at (−2,3) and (−2,−1).
Yes, at left parenthesis negative 2 comma 3 right parenthesis and left parenthesis negative 2 comma negative 1 right parenthesis .
Yes, at (−2,−1).
Responses
No, all endpoints are closed.
No, all endpoints are closed.
Yes, at (−2,3).
Yes, at left parenthesis negative 2 comma 3 right parenthesis .
Yes, at (−2,3) and (−2,−1).
Yes, at left parenthesis negative 2 comma 3 right parenthesis and left parenthesis negative 2 comma negative 1 right parenthesis .
Yes, at (−2,−1).
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To analyze the piecewise function \( f(x) \):
1. **Function Definition**:
- For \( x \leq -2 \), \( f(x) = x + 5 \)
- For \( x > -2 \), \( f(x) = 2x + 3 \)
2. **Finding the function values at \( x = -2 \)**:
- For \( x = -2 \):
- If \( x \leq -2 \), \( f(-2) = -2 + 5 = 3 \)
- If \( x > -2 \), \( f(-2) \) is not defined.
3. **Endpoints**:
- At \( x = -2 \), the function has a value \( f(-2) = 3 \) (from the first piece).
- The next piece, \( f(x) = 2x + 3 \), will not include the value at \( x = -2 \) since it only applies for \( x > -2 \).
Therefore, there is an open endpoint at \( (-2, 3) \) because while it is included in the first piece, the second piece does not include this point.
### Conclusion
Yes, there is an open endpoint at \( (-2, 3) \).
The correct response is:
**Yes, at (−2, 3).**
1. **Function Definition**:
- For \( x \leq -2 \), \( f(x) = x + 5 \)
- For \( x > -2 \), \( f(x) = 2x + 3 \)
2. **Finding the function values at \( x = -2 \)**:
- For \( x = -2 \):
- If \( x \leq -2 \), \( f(-2) = -2 + 5 = 3 \)
- If \( x > -2 \), \( f(-2) \) is not defined.
3. **Endpoints**:
- At \( x = -2 \), the function has a value \( f(-2) = 3 \) (from the first piece).
- The next piece, \( f(x) = 2x + 3 \), will not include the value at \( x = -2 \) since it only applies for \( x > -2 \).
Therefore, there is an open endpoint at \( (-2, 3) \) because while it is included in the first piece, the second piece does not include this point.
### Conclusion
Yes, there is an open endpoint at \( (-2, 3) \).
The correct response is:
**Yes, at (−2, 3).**
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