Asked by Anonymous ;)
name the first five terms of each arithmetic sequence descried.
a_(1) =4, d=3
a_(1) =4, d=3
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Answered by
GPT-4o mini
To find the first five terms of the arithmetic sequence defined by \( a_1 = 4 \) (the first term) and \( d = 3 \) (the common difference), we can use the formula for the \( n \)-th term of an arithmetic sequence:
\[
a_n = a_1 + (n - 1) \times d
\]
Now, we can calculate the first five terms:
1. For \( n = 1 \):
\[
a_1 = 4
\]
2. For \( n = 2 \):
\[
a_2 = 4 + (2 - 1) \times 3 = 4 + 3 = 7
\]
3. For \( n = 3 \):
\[
a_3 = 4 + (3 - 1) \times 3 = 4 + 6 = 10
\]
4. For \( n = 4 \):
\[
a_4 = 4 + (4 - 1) \times 3 = 4 + 9 = 13
\]
5. For \( n = 5 \):
\[
a_5 = 4 + (5 - 1) \times 3 = 4 + 12 = 16
\]
Therefore, the first five terms of the arithmetic sequence are:
**4, 7, 10, 13, 16**.
\[
a_n = a_1 + (n - 1) \times d
\]
Now, we can calculate the first five terms:
1. For \( n = 1 \):
\[
a_1 = 4
\]
2. For \( n = 2 \):
\[
a_2 = 4 + (2 - 1) \times 3 = 4 + 3 = 7
\]
3. For \( n = 3 \):
\[
a_3 = 4 + (3 - 1) \times 3 = 4 + 6 = 10
\]
4. For \( n = 4 \):
\[
a_4 = 4 + (4 - 1) \times 3 = 4 + 9 = 13
\]
5. For \( n = 5 \):
\[
a_5 = 4 + (5 - 1) \times 3 = 4 + 12 = 16
\]
Therefore, the first five terms of the arithmetic sequence are:
**4, 7, 10, 13, 16**.
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