To analyze the equation of the parabola given by \( y = -5x^2 + 1 \), we can identify its key features.
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Standard Form: The equation is in the form \( y = ax^2 + bx + c \), where:
- \( a = -5 \)
- \( b = 0 \)
- \( c = 1 \)
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Vertex: The vertex of a parabola in standard form can be found using the formula \( x = -\frac{b}{2a} \).
- Here, \( x = -\frac{0}{2 \cdot -5} = 0 \).
- To find the y-coordinate of the vertex, substitute \( x = 0 \) back into the equation: \[ y = -5(0)^2 + 1 = 1. \]
- Thus, the vertex is at \( (0, 1) \).
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Direction: Since \( a = -5 < 0 \), the parabola opens downward.
Now, let's review the provided statements based on this analysis:
- The parabola will have a vertex at \( (-1, 0) \). (Incorrect)
- The parabola will have a vertex at \( (0, 0) \). (Incorrect)
- The parabola will have a vertex at \( (1, 0) \). (Incorrect)
- The parabola will open downwards. (Correct)
The correct statement is: The parabola will open downwards.