To determine the correct piecewise function from the provided options, we need to analyze the characteristics of each segment of the function according to the given conditions.
1. Identify Each Piece of the Function:
- For \( x < -1 \), does the function appear to be \( x + 2 \)?
- For \( -1 \leq x \leq 1 \), does the function appear to be \( x + 3 \)?
- For \( x > 1 \), does the function appear to be \( x + 1 \)?
2. Analyzing the Options:
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First Option: \[ y = \begin{cases} x + 2 & \text{if } x < -1 \ x + 3 & \text{if } -1 \leq x \leq 1 \ x + 1 & \text{if } x > 1 \end{cases} \]
- This structure matches the described segments.
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Second Option: \[ y = \begin{cases} x + 2 & \text{if } x \leq -1 \ x + 3 & \text{if } 2 < x < 4 \ x + 1 & \text{if } x \geq 2 \end{cases} \]
- This option does not match the segments since it misplaces conditions.
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Third Option: \[ y = \begin{cases} x + 1 & \text{if } x \leq -1 \ x + 2 & \text{if } -1 < x < 1 \ x + 3 & \text{if } x \geq 1 \end{cases} \]
- The order of segments here does not correspond to the description.
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Fourth Option: \[ y = \begin{cases} x + 2 & \text{if } x \leq -1 \ x + 3 & \text{if } -1 < x < 1 \ x + 1 & \text{if } x \geq 1 \end{cases} \]
- This also does not match the conditions set earlier.
Conclusion: The first option accurately represents the piecewise function described. Therefore, the correct answer is:
\[ \boxed{y = \begin{cases} x + 2 & \text{if } x < -1 \ x + 3 & \text{if } -1 \leq x \leq 1 \ x + 1 & \text{if } x > 1 \end{cases}} \]