Question
It was reported that last year the average price of a gallon gasoline in a city X was $3.15. This year a sample of 50 gas station had an average price of $3.10 for a gallon. We assume that the population standard deviation of prices is $0.15. We are interested in determining whether this year mean price is less than last year. Perform a hypothesis test at the level of significance α=0.05.The assumptions are satisfied:
It is a simple random sample The sample size is
so it is more than required number 30.
It is a simple random sample The sample size is
so it is more than required number 30.
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GPT-4o mini
In order to determine if the average price of gasoline this year is less than the average price last year, we will conduct a hypothesis test using the following steps:
### Step 1: Define the null and alternative hypotheses
- **Null hypothesis (H0)**: μ = 3.15 (The average price of gasoline this year is equal to last year)
- **Alternative hypothesis (H1)**: μ < 3.15 (The average price of gasoline this year is less than last year)
### Step 2: Set the significance level
The significance level (α) is given as 0.05.
### Step 3: Test statistic and calculation
We will use a z-test for this hypothesis test because the population standard deviation is known and the sample size is large (n > 30).
The formula for the z-test statistic is:
\[
z = \frac{\bar{x} - \mu_0}{\frac{\sigma}{\sqrt{n}}}
\]
Where:
- \(\bar{x} = 3.10\) (sample mean)
- \(\mu_0 = 3.15\) (population mean under the null hypothesis)
- \(\sigma = 0.15\) (population standard deviation)
- \(n = 50\) (sample size)
Now, plug in the values:
\[
z = \frac{3.10 - 3.15}{\frac{0.15}{\sqrt{50}}} = \frac{-0.05}{\frac{0.15}{7.071}} = \frac{-0.05}{0.021213} \approx -2.36
\]
### Step 4: Determine the critical value
For a one-tailed test at the 0.05 significance level, we'll look up the critical z-value in a z-table or use a calculator. The critical z-value for a left-tailed test (α = 0.05) is approximately:
- **Critical z-value:** -1.645
### Step 5: Make a decision
Now, we compare the calculated z-value to the critical z-value:
- **Calculated z-value:** -2.36
- **Critical z-value:** -1.645
Since -2.36 < -1.645, we reject the null hypothesis.
### Conclusion
There is sufficient evidence to support the claim that the average price of gasoline this year is less than last year's average price of $3.15 at the 0.05 significance level.
### Step 1: Define the null and alternative hypotheses
- **Null hypothesis (H0)**: μ = 3.15 (The average price of gasoline this year is equal to last year)
- **Alternative hypothesis (H1)**: μ < 3.15 (The average price of gasoline this year is less than last year)
### Step 2: Set the significance level
The significance level (α) is given as 0.05.
### Step 3: Test statistic and calculation
We will use a z-test for this hypothesis test because the population standard deviation is known and the sample size is large (n > 30).
The formula for the z-test statistic is:
\[
z = \frac{\bar{x} - \mu_0}{\frac{\sigma}{\sqrt{n}}}
\]
Where:
- \(\bar{x} = 3.10\) (sample mean)
- \(\mu_0 = 3.15\) (population mean under the null hypothesis)
- \(\sigma = 0.15\) (population standard deviation)
- \(n = 50\) (sample size)
Now, plug in the values:
\[
z = \frac{3.10 - 3.15}{\frac{0.15}{\sqrt{50}}} = \frac{-0.05}{\frac{0.15}{7.071}} = \frac{-0.05}{0.021213} \approx -2.36
\]
### Step 4: Determine the critical value
For a one-tailed test at the 0.05 significance level, we'll look up the critical z-value in a z-table or use a calculator. The critical z-value for a left-tailed test (α = 0.05) is approximately:
- **Critical z-value:** -1.645
### Step 5: Make a decision
Now, we compare the calculated z-value to the critical z-value:
- **Calculated z-value:** -2.36
- **Critical z-value:** -1.645
Since -2.36 < -1.645, we reject the null hypothesis.
### Conclusion
There is sufficient evidence to support the claim that the average price of gasoline this year is less than last year's average price of $3.15 at the 0.05 significance level.
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