Asked by ~christina~

The periods of oscillaton were measured down to 0.38s. How could this be done with common laboratory timers?
-a given hint is : are the times exact values?

I don't know how this would work b/c I've never heard of a timer or stopwatch thant can register a time of less than a sec and your hand wouldn't be able to hit the button fast enough anyways so I have no clue not even with the hint b/c if it was not an exact time then the closest on a normal stopwatch would be 1s b/c it goes from 1sec-another sec not a fraction of a sec.

Answers

Answered by bobpursley
Could you time 100 occilations, then divide by 100?

Answered by ~christina~
Hm..I guess you could but what would that prove??

but if the oscillation timed was 1sec 1sec and 1sec then I don't know what difference that would make...you'd get 1sec..right?

Isn't it the problem of the timer??
Answered by bobpursley
Yes, if you time 100 oscillations you avoid the timer problem. NOT time 1 oscillation 100 times, but 100 oscillations one time.
Answered by ~christina~
Oh..okay thanks Bob =D
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