Question

What is −6 7/12 − 4 1/3
?(1 point)

Answer 1

what is the answer

Answer 2

To subtract the mixed numbers \(-6 \frac{7}{12}\) and \(4 \frac{1}{3}\), we can follow these steps:

1. Convert the mixed numbers to improper fractions.
- For \(-6 \frac{7}{12}\):
\[
-6 \frac{7}{12} = -\left(6 \times 12 + 7\right)/12 = -\left(72 + 7\right)/12 = -79/12
\]

- For \(4 \frac{1}{3}\):
\[
4 \frac{1}{3} = 4 \times 3 + 1/3 = (12 + 1)/3 = 13/3
\]

2. Now, to subtract these two improper fractions, we need a common denominator. The least common multiple of 12 and 3 is 12.

- Convert \(13/3\) to have a denominator of 12:
\[
13/3 = (13 \times 4)/(3 \times 4) = 52/12
\]

3. Now we have:
\[
-79/12 - 52/12
\]

4. Combine the fractions:
\[
-79/12 - 52/12 = \frac{-79 - 52}{12} = \frac{-131}{12}
\]

5. Convert \(-131/12\) back to a mixed number:
- Dividing 131 by 12 gives 10 with a remainder of 11, so:
\[
-\frac{131}{12} = -10 \frac{11}{12}
\]

Thus, the result of \(-6 \frac{7}{12} - 4 \frac{1}{3}\) is \(-10 \frac{11}{12}\).

Answer 3

The answer to \(-6 \frac{7}{12} - 4 \frac{1}{3}\) is:

\[
-10 \frac{11}{12}
\]