In a proton linear accelerator, a 8.6 proton current hits a target.

Question

5.4×10^16 protons/second hit the target.
How much energy is delivered to the target each second if each proton has a kinetic energy of 26 MeV and loses all its energy in the target?
U = J/s
If the target is a 1.90kg block of copper, at what rate will its temperature increase if it is not cooled?
delta T/s = kg degrees/second

Answer 1

Convert MeV to Joules/proton and multiply that by 5.5*10^16 protons/s

That gives you the answer in watts (or J/s).

Watts divided by (mass * specific heat)
is the rate of temperature increase

You will need to look up the specific heat of copper.