To solve the problem, we need to find all \( x \) such that neither \( 2x \) nor \( -20x \) is in the interval \( (-\infty, -1) \).
Step 1: Analyze the inequalities
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For \( 2x \) not to be in the interval \( (-\infty, -1) \): \[ 2x \geq -1 \]
To isolate \( x \): \[ x \geq -\frac{1}{2} \]
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For \( -20x \) not to be in the interval \( (-\infty, -1) \): \[ -20x \geq -1 \]
This can be rewritten as: \[ 20x \leq 1 \] Dividing by 20 gives: \[ x \leq \frac{1}{20} \]
Step 2: Combine the inequalities
We now have two inequalities to consider:
- \( x \geq -\frac{1}{2} \)
- \( x \leq \frac{1}{20} \)
These can be combined to form the compound inequality: \[ -\frac{1}{2} \leq x \leq \frac{1}{20} \]
Conclusion
The values of \( x \) that satisfy both conditions are:
\[ \boxed{[-\frac{1}{2}, \frac{1}{20}]} \]