Asked by h
A train travels from city A to city B. The cities are 600 miles apart. The distance from city A at t hours
after the train leaves A is given by d(t) = 50t + t^2.
What is the average velocity of the train in miles per hour during the trip from A to B?
after the train leaves A is given by d(t) = 50t + t^2.
What is the average velocity of the train in miles per hour during the trip from A to B?
Answers
Answered by
bobpursley
average velocity= distancegone/time=
= 600miles/time
600=50t+t^2
t^2+50t-600=0
(t+60)(t-10)=0
t= 10 hours (negative time is not allowed).
average velocity= 600miles/10 hrs=60mph
This is not calculus.
= 600miles/time
600=50t+t^2
t^2+50t-600=0
(t+60)(t-10)=0
t= 10 hours (negative time is not allowed).
average velocity= 600miles/10 hrs=60mph
This is not calculus.
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