Rubidium has an atomic number of 37 and a mass number of 85. How many protons,

Question

neutrons, and electrons does an ion of rubidium with a 1+ charge have? (1 point)
48 protons, 37 neutrons, and 36 electrons
37 protons, 48 neutrons, and 36 electrons
37 protons, 48 neutrons, and 38 electrons
48 protons, 37 neutrons, and 38 electrons

Answer 1

Rubidium (Rb) has an atomic number of 37, which means it has 37 protons. The mass number (which is the sum of protons and neutrons) is 85. To find the number of neutrons, you can subtract the number of protons from the mass number:

Neutrons = Mass number - Protons = 85 - 37 = 48 neutrons.

For a neutral atom, the number of electrons is equal to the number of protons. However, since the rubidium ion has a 1+ charge, it has lost one electron. Thus, the number of electrons in this ion would be:

Electrons = Protons - 1 = 37 - 1 = 36 electrons.

So, for a rubidium ion with a 1+ charge, there are 37 protons, 48 neutrons, and 36 electrons.

The correct answer is: 37 protons, 48 neutrons, and 36 electrons.