Question

Add −8 1/5+4 1/5.

Answers

Answer
can you write that like (fraction)/(fraction)
Answer
no like, write it like (number)/(number)
Answer
-1\frac{3}{\ 10}+(-4\frac{2}{\ 15})
Answered by GPT-4o mini
To add the mixed numbers \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\), we'll first convert them to improper fractions:

1. Convert \(-8 \frac{1}{5}\):
\[
-8 \frac{1}{5} = -\left(8 \times 5 + 1\right)/5 = -\left(40 + 1\right)/5 = -41/5
\]

2. Convert \(4 \frac{1}{5}\):
\[
4 \frac{1}{5} = (4 \times 5 + 1)/5 = (20 + 1)/5 = 21/5
\]

Now we can perform the addition:
\[
-\frac{41}{5} + \frac{21}{5} = \frac{-41 + 21}{5} = \frac{-20}{5}
\]

Simplifying \(\frac{-20}{5}\):
\[
\frac{-20}{5} = -4
\]

So, the result of adding \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\) is:
\[
-4
\]
Answered by GPT-4o mini
Certainly! To add \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\) using a fraction format, we can write it as follows:

1. **Convert to improper fractions**:
- \(-8 \frac{1}{5} = -\frac{41}{5}\)
- \(4 \frac{1}{5} = \frac{21}{5}\)

2. **Add the fractions**:
\[
-\frac{41}{5} + \frac{21}{5} = \frac{-41 + 21}{5} = \frac{-20}{5}
\]

Therefore, the addition can be written as:
\[
\left(-\frac{41}{5} + \frac{21}{5}\right) = \frac{-20}{5}
\]

Final result:
\[
\frac{-20}{5} = -4
\]

So, in the requested format:
\[
\frac{-41}{5} + \frac{21}{5} = \frac{-20}{5}
\]
And the simplified result is:
\[
\frac{-20}{5} = -4
\]
Answered by GPT-4o mini
Got it! Here’s the addition of \(-8 \frac{1}{5}\) and \(4 \frac{1}{5}\) represented in the form of \((number)/(number)\):

1. **First, convert the mixed numbers to improper fractions**:
- \(-8 \frac{1}{5} = -\frac{41}{5}\)
- \(4 \frac{1}{5} = \frac{21}{5}\)

2. **Now, write the addition as a single fraction**:
\[
\frac{-41}{5} + \frac{21}{5} = \frac{-41 + 21}{5} = \frac{-20}{5}
\]

So, in the format you requested, the addition looks like this:
\[
\frac{-41 + 21}{5} = \frac{-20}{5}
\]
And the simplified result is:
\[
\frac{-20}{5} = -4
\]

Thus, you can see each step laid out in the desired format!
Answered by GPT-4o mini
To add the mixed numbers \(-1 \frac{3}{10}\) and \(-4 \frac{2}{15}\), we will follow these steps:

1. **Convert the mixed numbers to improper fractions**:

\(-1 \frac{3}{10}\):
\[
-1 \frac{3}{10} = -\left(1 \times 10 + 3\right)/10 = -\left(10 + 3\right)/10 = -\frac{13}{10}
\]

\(-4 \frac{2}{15}\):
\[
-4 \frac{2}{15} = -\left(4 \times 15 + 2\right)/15 = -\left(60 + 2\right)/15 = -\frac{62}{15}
\]

2. **Find a common denominator** for the improper fractions. The least common multiple (LCM) of 10 and 15 is 30.

3. **Convert each fraction to have the common denominator of 30**:

For \(-\frac{13}{10}\):
\[
-\frac{13}{10} = -\frac{13 \times 3}{10 \times 3} = -\frac{39}{30}
\]

For \(-\frac{62}{15}\):
\[
-\frac{62}{15} = -\frac{62 \times 2}{15 \times 2} = -\frac{124}{30}
\]

4. **Now add the fractions**:
\[
-\frac{39}{30} + -\frac{124}{30} = \frac{-39 - 124}{30} = \frac{-163}{30}
\]

So, the result of adding \(-1 \frac{3}{10}\) and \(-4 \frac{2}{15}\) is:
\[
-\frac{163}{30}
\]

5. **If needed, you can convert it back to a mixed number**:
\[
-\frac{163}{30} = -5 \frac{13}{30} \quad (\text{since } 163 \div 30 = 5 \text{ remainder } 13)
\]

Thus, the final result is:
\[
-\frac{163}{30} \text{ or } -5 \frac{13}{30}
\]