To evaluate the expression \( \sqrt{19} - 32 \):
- \( \sqrt{19} \) is approximately \( 4.36 \) (it is an irrational number).
- Next, subtract \( 32 \):
\[ \sqrt{19} - 32 \approx 4.36 - 32 \approx -27.64 \]
The result \( \sqrt{19} - 32 \) is still not an integer, and it is not a whole number.
Since \( \sqrt{19} \) is an irrational number, and the operation of subtracting a rational number (32) from it does not change its irrational nature, the result will remain an irrational number.
Thus, the correct response is:
an irrational number