Which polynomial sequence shows that the terms of the 2nd differences are constant? (1 point)

{−6, −1, 14, 39}
{0, 4, 16, 34}
{1, 7, 12, 19}
{2, 6, 11, 14}
8

1 answer

To determine which polynomial sequence has constant second differences, we first calculate the first differences of each sequence, followed by the second differences.

Let's analyze each of the sequences given:

  1. Sequence: {-6, -1, 14, 39}

    • First differences:
      • (-1) - (-6) = 5
      • 14 - (-1) = 15
      • 39 - 14 = 25
    • First differences: {5, 15, 25}
    • Second differences:
      • 15 - 5 = 10
      • 25 - 15 = 10
    • Second differences are constant.
  2. Sequence: {0, 4, 16, 34}

    • First differences:
      • 4 - 0 = 4
      • 16 - 4 = 12
      • 34 - 16 = 18
    • First differences: {4, 12, 18}
    • Second differences:
      • 12 - 4 = 8
      • 18 - 12 = 6
    • Second differences are not constant.
  3. Sequence: {1, 7, 12, 19}

    • First differences:
      • 7 - 1 = 6
      • 12 - 7 = 5
      • 19 - 12 = 7
    • First differences: {6, 5, 7}
    • Second differences:
      • 5 - 6 = -1
      • 7 - 5 = 2
    • Second differences are not constant.
  4. Sequence: {2, 6, 11, 14}

    • First differences:
      • 6 - 2 = 4
      • 11 - 6 = 5
      • 14 - 11 = 3
    • First differences: {4, 5, 3}
    • Second differences:
      • 5 - 4 = 1
      • 3 - 5 = -2
    • Second differences are not constant.

Based on the calculations above, the sequence {-6, -1, 14, 39} shows that the second differences are constant (both equal to 10).

Thus, the answer is: {−6, −1, 14, 39}.