Question
Calculate the density of a 9.00 x 10^2 g object that has a volume of 79.5 mL. Be sure your answer has the correct number of significant figures.
Answers
GPT-4o mini
To calculate the density of an object, you can use the formula:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
In this case, the mass of the object is \( 9.00 \times 10^2 \, \text{g} = 900 \, \text{g} \) and the volume is \( 79.5 \, \text{mL} \).
Now, substituting the values into the formula:
\[
\text{Density} = \frac{900 \, \text{g}}{79.5 \, \text{mL}} \approx 11.39 \, \text{g/mL}
\]
Next, we need to consider significant figures in our answer.
- The mass \( 9.00 \times 10^2 \, \text{g} \) has 3 significant figures.
- The volume \( 79.5 \, \text{mL} \) has 3 significant figures as well.
When performing division, the result should be reported to the least number of significant figures in the values used for the calculation. Therefore, we round our result to 3 significant figures:
\[
\text{Density} \approx 11.4 \, \text{g/mL}
\]
So, the final answer with the correct number of significant figures is:
\[
\boxed{11.4 \, \text{g/mL}}
\]
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
In this case, the mass of the object is \( 9.00 \times 10^2 \, \text{g} = 900 \, \text{g} \) and the volume is \( 79.5 \, \text{mL} \).
Now, substituting the values into the formula:
\[
\text{Density} = \frac{900 \, \text{g}}{79.5 \, \text{mL}} \approx 11.39 \, \text{g/mL}
\]
Next, we need to consider significant figures in our answer.
- The mass \( 9.00 \times 10^2 \, \text{g} \) has 3 significant figures.
- The volume \( 79.5 \, \text{mL} \) has 3 significant figures as well.
When performing division, the result should be reported to the least number of significant figures in the values used for the calculation. Therefore, we round our result to 3 significant figures:
\[
\text{Density} \approx 11.4 \, \text{g/mL}
\]
So, the final answer with the correct number of significant figures is:
\[
\boxed{11.4 \, \text{g/mL}}
\]