Rewrite the expression 125 2/3 as a product of identical factors to find the product. Submit your answer in simplified form. Remember to simplify using the denominator of the exponent before applying the numerator on the exponent

3 answers

To rewrite 12523 as a product of identical factors, we can first convert the mixed number to an improper fraction.

  1. Convert 12523 to an improper fraction: 12523=125+23=12533+23=375+23=3773

Next, we want to express 3773 as a product of identical factors.

  1. Since 377=125+2 doesn't factor nicely, let's look at 125. 125=53

Thus, 12523=533+23=53+23, but 53+2 does not lead to a simpler form.

  1. Since we are interested in representing 12523 in exponents: 12523=53(23)

Applying the exponent property, simplify 5323: =5323

While we can't simplify this significantly further, we can express the fraction: =2×1253=2503

Thus, the final simplified form of the expression 12523 as a product of identical factors is: =2503

Therefore, the answer is: 2503

No

I apologize for any confusion. Let's correctly rewrite 12523 as a product of identical factors and simplify correctly.

  1. First, let's convert the mixed number 12523 into an improper fraction: 12523=125+23=12533+23=375+23=3773

  2. Now, we can write 3773 in terms of powers and see if there's a way to express it as a product of identical factors. However, 377 is not a perfect power, so let's break this down:

  3. Instead, 125 can be factored as 53 because: 125=53 Thus, we can treat 12523 as: 12523=12523=5323

  4. To express this using exponents, recognize that 23 does not relate to the base 5. However, we want to express 53 as identical factors: 53=555

So, we get: 12523=2(555)3

Since we're looking for the product of identical factors involving exponents:

  1. To express 12523 in simplified form without fractions, we might treat it as: 12523=(532)13

The simplified expression remains: 2503 (This was our earlier result correctly presented, not an identical factor of 125 itself).

Alternatively, if looking just for products of identical factors relating back to mixed number and factoring: 125=53 But not leading to the same profound simplification as 125.

Thus, a clearer result obtaining identical factor solution:

  • Expressed 12523 as:
    • Identical factors are 5,5,5. Further factoring with 2/3.

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