Using a number line, what is the approximate number value of 103−−−√? Provide your answer in decimal form, rounded to the nearest hundredth

1 answer

To approximate \(\sqrt{103}\), we can find two perfect squares it falls between.

The perfect squares close to 103 are:

  • \(10^2 = 100\)
  • \(11^2 = 121\)

Thus, \(\sqrt{103}\) is between 10 and 11.

Next, we'll refine our estimate further:

  1. Estimate between 10 and 11: Check \(10.1\): \[ 10.1^2 = 102.01 \] This is less than 103.

  2. Check \(10.2\): \[ 10.2^2 = 104.04 \] This is greater than 103.

So, we know \(\sqrt{103}\) is between 10.1 and 10.2.

  1. Narrow it down further: Check \(10.15\): \[ 10.15^2 = 103.0225 \] This is greater than 103.

  2. Check \(10.14\): \[ 10.14^2 = 103.0596 \] This is also greater than 103.

  3. Check \(10.13\): \[ 10.13^2 = 102.6569 \] This is less than 103.

Now we know:

  • \(\sqrt{103}\) is between \(10.13\) and \(10.15\).
  1. Further refine by trying \(10.14\) again with more checks:
    • Reiterating for higher precision, let's also check \(10.141\): \[ 10.141^2 = 102.853881 \] This is still less than 103.

Continuing this process lets us get closer:

After checking around the numbers, we determine \(\sqrt{103} \approx 10.14\) to \(10.15\).

Finally: Using a calculator or high precision tables, we find: \[ \sqrt{103} \approx 10.148 \] In decimal form, rounded to the nearest hundredth, this gives us:

\[ \boxed{10.15} \]