Gregory has a rectangular prism with a length of 10 cm, a width of 3 cm, and a height of 8 cm.

What is the surface area of Gregory's rectangular prism?
134 cm²
240 cm²
268 cm²
486 cm²

1 answer

To find the surface area of a rectangular prism, you can use the formula:

\[ \text{Surface Area} = 2(lw + lh + wh) \]

where \( l \) is the length, \( w \) is the width, and \( h \) is the height of the prism.

Given:

  • Length \( l = 10 \) cm
  • Width \( w = 3 \) cm
  • Height \( h = 8 \) cm

Now, plug the values into the formula:

  1. Calculate \( lw \): \[ lw = 10 \times 3 = 30 , \text{cm}^2 \]

  2. Calculate \( lh \): \[ lh = 10 \times 8 = 80 , \text{cm}^2 \]

  3. Calculate \( wh \): \[ wh = 3 \times 8 = 24 , \text{cm}^2 \]

  4. Sum these areas: \[ lw + lh + wh = 30 + 80 + 24 = 134 , \text{cm}^2 \]

  5. Now multiply by 2 to get the total surface area: \[ \text{Surface Area} = 2 \times 134 = 268 , \text{cm}^2 \]

Therefore, the surface area of Gregory's rectangular prism is \( \boxed{268 , \text{cm}^2} \).