Asked by Hannah
Solving log functions
1) log x + log(x-6) = log 7
1) log x + log(x-6) = log 7
Answers
Answered by
bobpursley
adding logs is same as multiplying the arguements.
LogA+LogB= log(AB)
log(x(x-6))=log7
take the antilog of each side.
x(x-6)=7
solve.
LogA+LogB= log(AB)
log(x(x-6))=log7
take the antilog of each side.
x(x-6)=7
solve.
Answered by
drwls
Note that
x^2 -6x -7 = 0
is easily factored.
There are two solutions that are integers. Only the positive root is allowed, however, since the log of a negative number is undefined.
x^2 -6x -7 = 0
is easily factored.
There are two solutions that are integers. Only the positive root is allowed, however, since the log of a negative number is undefined.
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