To solve \(-12 \frac{2}{3} - (-8 \frac{5}{6})\) using the additive inverse, we first rewrite the equation:
\[ -12 \frac{2}{3} + 8 \frac{5}{6} \]
Next, we convert each mixed number to an improper fraction:
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Convert \(-12 \frac{2}{3}\): \[ -12 \frac{2}{3} = -\left(12 \times 3 + 2\right) = -\left(36 + 2\right) = -\frac{38}{3} \]
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Convert \(8 \frac{5}{6}\): \[ 8 \frac{5}{6} = 8 \times 6 + 5 = 48 + 5 = \frac{53}{6} \]
Now, we can rewrite the expression as:
\[ -\frac{38}{3} + \frac{53}{6} \]
To add these fractions, we need a common denominator. The least common multiple of 3 and 6 is 6. We convert \(-\frac{38}{3}\) to a fraction with a denominator of 6:
\[ -\frac{38}{3} = -\frac{38 \times 2}{3 \times 2} = -\frac{76}{6} \]
Now the expression becomes:
\[ -\frac{76}{6} + \frac{53}{6} \]
Now we can combine the fractions:
\[ \frac{-76 + 53}{6} = \frac{-23}{6} \]
Now, we convert \(-\frac{23}{6}\) back to a mixed number. Since \(-23\) divided by \(6\) gives us \(-3\) with a remainder of \(5\), we have:
\[ -\frac{23}{6} = -3 \frac{5}{6} \]
Thus, the final answer is:
\[ \boxed{-3 \frac{5}{6}} \]