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Using rational approximations, what statement is true? (1 point) √16 > 4 12 < π 12 > π √16 < 4Asked by bruh no
Using rational approximations, what statement is true?(1 point)
16−−√>4
16 −−−√<4
12 −−−√<π
12 −−−√ >π
16−−√>4
16 −−−√<4
12 −−−√<π
12 −−−√ >π
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Answered by
GPT-4o mini
To analyze the statements using rational approximations, let's evaluate each one:
1. **\( \sqrt{16} > 4 \)**:
\( \sqrt{16} = 4 \)
So, \( \sqrt{16} > 4 \) is **false**.
2. **\( \sqrt{16} < 4 \)**:
\( \sqrt{16} = 4 \)
So, \( \sqrt{16} < 4 \) is **false**.
3. **\( \sqrt{12} < \pi \)**:
We know \( \sqrt{12} \approx 3.464 \) and \( \pi \approx 3.14159 \).
So, \( \sqrt{12} < \pi \) is **false**.
4. **\( \sqrt{12} > \pi \)**:
Given \( \sqrt{12} \approx 3.464 \) and \( \pi \approx 3.14159 \),
We find \( \sqrt{12} > \pi \) is **true**.
Therefore, the correct statement is:
**\( \sqrt{12} > \pi \)**.
1. **\( \sqrt{16} > 4 \)**:
\( \sqrt{16} = 4 \)
So, \( \sqrt{16} > 4 \) is **false**.
2. **\( \sqrt{16} < 4 \)**:
\( \sqrt{16} = 4 \)
So, \( \sqrt{16} < 4 \) is **false**.
3. **\( \sqrt{12} < \pi \)**:
We know \( \sqrt{12} \approx 3.464 \) and \( \pi \approx 3.14159 \).
So, \( \sqrt{12} < \pi \) is **false**.
4. **\( \sqrt{12} > \pi \)**:
Given \( \sqrt{12} \approx 3.464 \) and \( \pi \approx 3.14159 \),
We find \( \sqrt{12} > \pi \) is **true**.
Therefore, the correct statement is:
**\( \sqrt{12} > \pi \)**.
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