Asked by RMZ
how do you solve this
Area of a polygon: A=1/2aP
Perimeter: P=ns
It is a hexagon (6 sides) the sides measure 8cm therefore I have a perimeter measuring
P=6(8)=48 RIGHT?
and for the area I have A=1/2 the apothem= 4 square root of 3 and the P= 48
so, A=1/2(4 square root of 3)48, but how do you solve that??
Area of a polygon: A=1/2aP
Perimeter: P=ns
It is a hexagon (6 sides) the sides measure 8cm therefore I have a perimeter measuring
P=6(8)=48 RIGHT?
and for the area I have A=1/2 the apothem= 4 square root of 3 and the P= 48
so, A=1/2(4 square root of 3)48, but how do you solve that??
Answers
Answered by
Reiny
your answer of
Area = (1/2)(4√3)(48)
= 96√3
should be an acceptable answer, since it is "exact".
If you want a decimal equivalent, you can use your calculator.
Area = (1/2)(4√3)(48)
= 96√3
should be an acceptable answer, since it is "exact".
If you want a decimal equivalent, you can use your calculator.