\left(4-2x\right)\left(\frac{-6x^2+10x+21}{4-2x}\right)

1 answer

To simplify the expression \(\left(4-2x\right)\left(\frac{-6x^2+10x+21}{4-2x}\right)\), we can cancel out the common factor \((4-2x)\) from the numerator and the denominator, as long as \(4-2x \neq 0\):

  1. Identify the factor that can be canceled: \[ 4 - 2x \neq 0 \Rightarrow x \neq 2 \]

  2. Cancel the common factor: \[ \left(4-2x\right) \left(\frac{-6x^2+10x+21}{4-2x}\right) = -6x^2 + 10x + 21 \quad \text{(for \(x \neq 2\))} \]

Thus, the simplified expression is: \[ -6x^2 + 10x + 21 \quad \text{(for \(4 - 2x \neq 0\))} \]