Find the following probabilities, if X is an uniform variable whose density function is shown below. Write as a decimal.

P(X<45) =

P(12<X<32) =

1 answer

To find the probabilities for a uniform random variable \( X \), we need to know the range of the uniform distribution.

  1. The cumulative distribution function (CDF) gives the probability \( P(X < x) \). For a uniform distribution defined on the interval \([a, b]\), the CDF is given by:

    \[ P(X < x) = \frac{x - a}{b - a} \quad \text{for } a \leq x \leq b \]

  2. The probability of \( P(a < X < b) \) can be calculated as:

    \[ P(a < X < b) = \frac{b - a}{d - c} \]

    where \( [c, d] \) is the interval of the uniform variable.

Without the specific range of \( X \) provided, let's assume \( X \) ranges from \( a \) to \( b \).

Assumptions:

Let's assume \( X \) is uniformly distributed in the interval \([10, 50]\).

Now, let's calculate the probabilities based on these assumptions:

  1. For \( P(X < 45) \): \[ P(X < 45) = \frac{45 - 10}{50 - 10} = \frac{35}{40} = 0.875 \]

  2. For \( P(12 < X < 32) \): \[ P(12 < X < 32) = \frac{32 - 12}{50 - 10} = \frac{20}{40} = 0.5 \]

Summary:

  • \( P(X < 45) = 0.875 \)
  • \( P(12 < X < 32) = 0.5 \)

Please provide the specific range of the uniform variable if different from this assumption for accurate calculations.

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